24n^2+29n-63=0

Solution for 24n^2+29n-63=0 equation:

24n^2+29n-63=0

a = 24; b = 29; c = -63;
Δ = b2-4ac
Δ = 292-4·24·(-63)
Δ = 6889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6889}=83$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-83}{2*24}=\frac{-112}{48}
=-2+1/3
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+83}{2*24}=\frac{54}{48}
=1+1/8
$